I would like to call a function that is inside another function, that function will clear the timeout.
I have tried the following code, but without success:
async function Blast2() {
const delayTime = 1000;
const timer = (ms) => new Promise((res) => setTimeout(res, ms));
function ClearDelayTime() {
return clearTimeout(blast);
}
const blast = setTimeout(function () {
let blast =
"SELECT * FROM admin_contacts,temporary WHERE blast_status = 'sended'";
db.query(blast, async function (err, result, field) {
if (err) throw err;
loop: {
for (var i = 0; i < result.length; i ) {
console.log(result[i].telefone);
await timer(delayTime); // then the created Promise can be awaited
}
}
});
}, delayTime);
}
// I Want Call the function ClearDelayTime() inside Blast2()
Blast2().ClearDelayTime();
CodePudding user response:
I've refactored your code. It now immediately returns a function that can be used to abort.
const db = {
query: (sql, callback) => callback(undefined,
[{telefone:1},{telefone:2},{telefone:3},{telefone:4},{telefone:5}])
}
function blast2() {
const delayTime = 1000
const timer = ms => new Promise(res => setTimeout(res, ms))
let sql = "SELECT * FROM admin_contacts,temporary WHERE blast_status = 'sended'";
let abort = false;
db.query(sql, (err, result) => {
if (!err) {
(async () => {
for(let i=0; i<result.length && !abort; i ) {
console.log(result[i].telefone);
await timer(delayTime);
}
})();
}
})
return () => abort = true;
}
let abortFunc = blast2();
setTimeout(abortFunc, 2500);
CodePudding user response:
Your function Blast2
doesn't return anything. If you want to call a function inside it, you could return and store it using a variable, then call it.
Something like this:
const f1 = () => {
console.log('f1 called')
const f2 = () => {
console.log('f2 called')
}
return f2
}
const returnedFunction = f1()
console.log(returnedFunction())