How to get the name of nested tag from xml python-CodePudding

I want to get the name of all tags of nested tag. here is the code that I tried

soup = BeautifulSoup('''
<AlternativeIdentifiers>
   <NationalLocationCode>513100</NationalLocationCode>
</AlternativeIdentifiers>
<Name>Abbey Wood</Name>
<SixteenCharacterName>ABBEY WOOD.</SixteenCharacterName>
<Address>
 <com:PostalAddress>
   <add:A_5LineAddress>
       <add:Line>Abbey Wood station</add:Line>
       <add:Line>Wilton Road</add:Line>
       <add:Line>Abbey Wood</add:Line>
       <add:Line>Greater London</add:Line>
       <add:PostCode>SE2 9RH</add:PostCode>
   </add:A_5LineAddress>
 </com:PostalAddress>
</Address>
    ''', "lxml")

tags = content.find("AlternativeIdentifiers").name 

print(tags)

for example, it will print AlternativeIdentifiers but I want the inside tag name too which is NationalLocationCode. I tried using the for loop but got the error. Just for more clarification I have tried find_all and then use the for loop to traverse to get the tag name but it will print the entire tag not the tag.name

CodePudding user response：

Just invoke the find_all method, then you will get the desired ResultSet.

from bs4 import BeautifulSoup

soup = BeautifulSoup('''
<AlternativeIdentifiers>
   <NationalLocationCode>513100</NationalLocationCode>
</AlternativeIdentifiers>
<Name>Abbey Wood</Name>
<SixteenCharacterName>ABBEY WOOD.</SixteenCharacterName>
<Address>
 <com:PostalAddress>
   <add:A_5LineAddress>
       <add:Line>Abbey Wood station</add:Line>
       <add:Line>Wilton Road</add:Line>
       <add:Line>Abbey Wood</add:Line>
       <add:Line>Greater London</add:Line>
       <add:PostCode>SE2 9RH</add:PostCode>
   </add:A_5LineAddress>
 </com:PostalAddress>
</Address>
    ''', "xml")

for tag in tags:
    print(tag.name)
    print(tag.find('NationalLocationCode').name)

Output:

AlternativeIdentifiers
NationalLocationCode

CodePudding user response：

when you define the soup variable like this the tag names get changed. try to print soup variable you will get your answer.

do print(soup) once