how do I achieve this in Python? Source file is a CSV file, and value of one column in that file is converted from numeric to day and month. Thank you very much in advance.

Example below:

Picture of the column: room column

In my python script, value should look below:

1-Feb ---> 2-1
2-Feb ---> 2-2
3-Mar ---> 3-3
4-Mar ---> 3-4

Here's my script.

import os
import pandas as pd

directory = 'C:/Path'
ext = ('.csv')

for filename in os.listdir(directory):
f = os.path.join(directory, filename)

if f.endswith(ext):

    head_tail = os.path.split(f)
    head_tail1 = 'C:/Path'
    k =head_tail[1]
    r=k.split(".")[0]

    p=head_tail1   "/"   r   " - Revised.csv"
    mydata = pd.read_csv(f)


    # to pull columns and values
    new = mydata[["A","Room","C","D"]]
    new = new.rename(columns={'D': 'Qty. of Parts'})
    new['Qty. of Parts'] = 1
    new.to_csv(p ,index=False)

    #to merge columns and values
    merge_columns = ['A', 'Room', 'C']
    merged_col = ''.join(merge_columns).replace('ARoomC', 'F')
    new[merged_col] = new[merge_columns].apply(lambda x: '.'.join(x), axis=1)

    new.drop(merge_columns, axis=1, inplace=True)
    new = new.groupby(merged_col).count().reset_index()
    new.to_csv(p, index=False)

CodePudding user response：

If you want to convert the strings to dates to later get the values

import datetime
# datetime.datetime(1900, 2, 1, 0, 0)
d = datetime.datetime.strptime("1-Feb", "%d-%b")
print(f'{d.month}-{d.day}')

result:

2-1

CodePudding user response：

You can use pandas.to_datetime :

new["Room"]= (
                pd.to_datetime(new["Room"], format="%d-%b", errors="coerce")
                    .dt.strftime("%#m-%#d")
                    .fillna(new["Room"])
                )

Example :

     col
0  1-Feb
1  2-Feb
2  3-Mar
3    2-1

Gives :

   col
0  2-1
1  2-2
2  3-3
3  2-1

NB: In case you're facing errors, you need to give a minimal reproducible example to show how look like your original (.csv) opened in a text editor and not in Excel.