How to display all even number that are smaller or equal to the number inserted-CodePudding

How to create a code in c that if I insert any number "n" it displays all the "even" numbers that are smaller or equal to "n"

I dont have much knowledge in C so I would appreciate the help

CodePudding user response：

This is what I tried and think it's good enough

int n;

cout << "\nEnter number=  ";
cin >> n;

cout << "\nEven numbers are ";
for(int i = 0; i <= n; i  )
{
    if ( i % 2 == 0 )
    {
        cout << i <<" ";
    }
}

CodePudding user response：

You can use a repetition loop to check for all the numbers until N and the look if each number is divisible by 2 (when, in that division, the remainder is 0).

@john ideia of starting counting at 2 and going up 2 at a time is a easier one.