How to retrieve stored Python object from dictionary?-CodePudding

I have a Python dictionary dict1:

import gradio as gr

dict1 = {
    "x" : 2,
    "y" : 110,
    "z" : gr.Dropdown(label="zip", choices=["12345", "98765"], value="44445")
}

The key z contains a Gradio object.

In the next step I want to convert all my dict keys to proper variables:

for var in dict1:
    locals()[var] = dict1[var]

This kind of works as you can see:

print(dict1)
print(x,y, z)
type(z)
>>>> {'x': 2, 'y': 110, 'z': dropdown}
>>>> 2 110 dropdown
>>>> gradio.components.Dropdown

However, the object in dict1 is not showing all informations. Its still an object but I want z to be z = gr.Dropdown(label="zip", choices=["12345", "98765"], value="44445"). At the moment it is z = dropdown

How can I do it?

CodePudding user response：

Once gr.Dropdown is constructed Python interpretor won't know which parameters were used to construct the object.

But you can print all fields of the object with the following function:

def pretty_print(clas, indent=0):
    print(' ' * indent    type(clas).__name__    ':')
    indent  = 4
    for k,v in clas.__dict__.items():
        print(' ' * indent    k   ': '   str(v))

Now you can run:

pretty_print(dict1['z'])

to get the output:

Dropdown:
    choices: ['12345', '98765']
    type: value
    test_input: 12345
    interpret_by_tokens: False
    label: zip
    show_label: True
    requires_permissions: False
    interactive: None
    value: 44445
    attach_load_event: False
    load_fn: None
    _id: 0
    visible: True
    elem_id: None
    root_url: None
    _style: {}
    cleared_value: 44445

This output contains more fields but the useful fields are all here.