How to split binary array into two?-CodePudding

Here is my array:

['1011000111001100', '0010110101100111', '0010101011111111', '1010111001101001', '1010110101000101', '1001011111001001', '1010110000001111', '1011000000111001', '0011000101001101', '1011000110100100', '0011000010100110', '1010100111110100', '1011000010100111', '1010000100111000', '1010110001110011', '0011001100101101', '1010111101011010', '1011000011010010', '1010111100010100', '1010101111001000', '0001100000111110', '1010100000010111', '1001110111101000', '0010110111000000', '1010111001011001', '1011011010010011', '1010111100010110', '1010110001010100', '1010011111100000', '1010100001111100', '1010101100110100', '0010101000001000', '1011001010010111', '1010100000000001', '0010010010000011', '0010111001100101', '0001100101010100', '1010100111001011', '0011000001110110', '1010001010101101', '1011001001100000', '0001100001110000', '0011000101101111', '0011001111111010', '0011000101100000', '0010100001011110', '0010110000001000', '1010101010010100', '0010111111001110', '1011010000001100', '1000111110000101', '0010100101101001', '0010110100111011', '0010011101110110', '0010111111101001', '1011000010010111', '0010101001011010', '0011000000000011', '1011000101001100', '0010110010001011', '0010000000001101', '1010111001000101', '1010110011100010', '1010100101000111']

Now I need to split each element into 2. What I mean is from '1011000111001100' to '10110001', '11001100'. How will I do that? Please help me to make program about this

CodePudding user response：

You would iterate (loop) through each element of the list, split the current element and add it to another list (or whatever fits your problem better)

You can split a string using the string slicing operator:

s = "Hello, World!"
print(s[:3])
# "Hel"

splittedBinaryArray = []

for element in binaryArray:
    leftSide = element[:8] # From start to 16th bit
    rightSide = element[8:] # From 16th bit to end
    
    splittedBinaryArray.append([leftSide, rightSide])  # Add to new array

This is the result:

[['10110001', '11001100'], ['00101101', '01100111'], ['00101010', '11111111'], ...]

You maybe want to even convert the binary to an integer value if needed:

int("10110001", 2)  # Base 2
# 89

CodePudding user response：

Code:-

lis=['1011000111001100', '0010110101100111', '0010101011111111', '1010111001101001', '1010110101000101', '1001011111001001', '1010110000001111', '1011000000111001', '0011000101001101', '1011000110100100', '0011000010100110', '1010100111110100', '1011000010100111', '1010000100111000', '1010110001110011', '0011001100101101', '1010111101011010', '1011000011010010', '1010111100010100', '1010101111001000', '0001100000111110', '1010100000010111', '1001110111101000', '0010110111000000', '1010111001011001', '1011011010010011', '1010111100010110', '1010110001010100', '1010011111100000', '1010100001111100', '1010101100110100', '0010101000001000', '1011001010010111', '1010100000000001', '0010010010000011', '0010111001100101', '0001100101010100', '1010100111001011', '0011000001110110', '1010001010101101', '1011001001100000', '0001100001110000', '0011000101101111', '0011001111111010', '0011000101100000', '0010100001011110', '0010110000001000', '1010101010010100', '0010111111001110', '1011010000001100', '1000111110000101', '0010100101101001', '0010110100111011', '0010011101110110', '0010111111101001', '1011000010010111', '0010101001011010', '0011000000000011', '1011000101001100', '0010110010001011', '0010000000001101', '1010111001000101', '1010110011100010', '1010100101000111']
res=[]
for binary in lis:
    res.append(binary[:len(binary)//2])
    res.append(binary[len(binary)//2:])
print(res)

Output:-

['10110001', '11001100', '00101101', '01100111', '00101010', '11111111', '10101110', '01101001', '10101101', '01000101', '10010111', '11001001', '10101100', '00001111', '10110000', '00111001', '00110001', '01001101', '10110001', '10100100', '00110000', '10100110', '10101001', '11110100', '10110000', '10100111', '10100001', '00111000', '10101100', '01110011', '00110011', '00101101', '10101111', '01011010', '10110000', '11010010', '10101111', '00010100', '10101011', '11001000', '00011000', '00111110', '10101000', '00010111', '10011101', '11101000', '00101101', '11000000', '10101110', '01011001', '10110110', '10010011', '10101111', '00010110', '10101100', '01010100', '10100111', '11100000', '10101000', '01111100', '10101011', '00110100', '00101010', '00001000', '10110010', '10010111', '10101000', '00000001', '00100100', '10000011', '00101110', '01100101', '00011001', '01010100', '10101001', '11001011', '00110000', '01110110', '10100010', '10101101', '10110010', '01100000', '00011000', '01110000', '00110001', '01101111', '00110011', '11111010', '00110001', '01100000', '00101000', '01011110', '00101100', '00001000', '10101010', '10010100', '00101111', '11001110', '10110100', '00001100', '10001111', '10000101', '00101001', '01101001', '00101101', '00111011', '00100111', '01110110', '00101111', '11101001', '10110000', '10010111', '00101010', '01011010', '00110000', '00000011', '10110001', '01001100', '00101100', '10001011', '00100000', '00001101', '10101110', '01000101', '10101100', '11100010', '10101001', '01000111']

CodePudding user response：

considering you want to devide it in half

x = ['1011000111001100', '0010110101100111', '0010101011111111', '1010111001101001', '1010110101000101', '1001011111001001', '1010110000001111', '1011000000111001', '0011000101001101', '1011000110100100', '0011000010100110', '1010100111110100', '1011000010100111', '1010000100111000', '1010110001110011', '0011001100101101', '1010111101011010', '1011000011010010', '1010111100010100', '1010101111001000', '0001100000111110', '1010100000010111', '1001110111101000', '0010110111000000', '1010111001011001', '1011011010010011', '1010111100010110', '1010110001010100', '1010011111100000', '1010100001111100', '1010101100110100', '0010101000001000', '1011001010010111', '1010100000000001', '0010010010000011', '0010111001100101', '0001100101010100', '1010100111001011', '0011000001110110', '1010001010101101', '1011001001100000', '0001100001110000', '0011000101101111', '0011001111111010', '0011000101100000', '0010100001011110', '0010110000001000', '1010101010010100', '0010111111001110', '1011010000001100', '1000111110000101', '0010100101101001', '0010110100111011', '0010011101110110', '0010111111101001', '1011000010010111', '0010101001011010', '0011000000000011', '1011000101001100', '0010110010001011', '0010000000001101', '1010111001000101', '1010110011100010', '1010100101000111']
result = [i[j:j len(i)//2] for i in x for j in range(0, len(i), len(i)//2)]

CodePudding user response：

(Arrays in Python are called "lists" so don't be confused if I call them that in this answer.)

This question is actually 2 questions:

how to split string into two parts?

Assuming the string always have 16 characters, you can use the slicing operator:

left_part = your_string[:8]
right_part = your_string[8:]

Or if the length of the string can vary:

left_part = your_string[:len(your_string)//2]
right_part = your_string[len(your_string)//2:]

How to convert a list to another one that have a different number of elements?

You can use a list comprehension:

new_array = [y for x in old_array for y in split_in_two(x)]

This iterates over the original list, splitting each of its element into 2, then it iterates ever these halves and create a new list out of them. If you don't like python list comprehensions, you can write the same in a more verbose way:

new_list = []
for x in old_list:
    for y in split_in_two(x):
        new_array.append(y)

If you put it all together, you get:

new_list = [y for x in old_list for y in (x[:8], x[8:])]