I am looking for if it is possible to get the data and headers from a table as in the example image and have the output go to two columns with the first column being a repeating header? I did try the transpose however the email row kept populating up to column E.
CodePudding user response:
Please, try the next way. It uses arrays being fast even for large ranges, mostly working in memory. It returns starting from "F2". It is able to process any other columns you (may) need, after "Status":
Sub TransposeMails()
Dim sh As Worksheet, lastR As Long, lastCol As Long
Dim arrH, arr, arrFin, i As Long, j As Long, k As Long
Set sh = ActiveSheet 'use here the necessary sheet
lastR = sh.Range("A" & sh.rows.count).End(xlUp).row 'last row
lastCol = sh.cells(1, sh.Columns.count).End(xlToLeft).column 'last column
arrH = Application.Transpose(sh.Range(sh.cells(1, 1), sh.cells(1, lastCol)).Value2) 'place headers in an array
arr = sh.Range("A2", sh.cells(lastR, lastCol)).Value2 'place the range to be processed (except headers) in an array for faster iteration/processing
ReDim arrFin(1 To (UBound(arrH) 1) * UBound(arr), 1 To 2) 'Redim the final array (keeping the processed result)
' 1 for the empty rows in between...
For i = 1 To UBound(arr)
For j = 1 To UBound(arrH)
k = k 1
arrFin(k, 1) = arrH(j, 1): arrFin(k, 2) = arr(i, j)
Next j
k = k 1 'for the empty row between groups...
Next i
'drop the processed array content:
sh.Range("G2").Resize(UBound(arrFin), 2).Value2 = arrFin
End Sub
The code can be easily adapted to return anywhere (another sheet, workbook, range etc).
The range to be processed must start from "A1" ("Email" header) and not having any other record after the last header (on the first row)...
CodePudding user response:
Transpose Data
Sub TransposeData()
Const SRC_NAME As String = "Sheet1"
Const DST_NAME As String = "Sheet1"
Const DST_FIRST_CELL As String = "A8"
Const EMPTY_COLS As Long = 0
Const EMPTY_ROWS As Long = 1
Dim wb As Workbook: Set wb = ThisWorkbook ' workbook containing this code
Dim sws As Worksheet: Set sws = wb.Sheets(SRC_NAME)
Dim srg As Range: Set srg = sws.Range("A1").CurrentRegion
Dim drOffset As Long: drOffset = srg.Columns.Count EMPTY_ROWS
Dim dcOffset As Long: dcOffset = 1 EMPTY_COLS
Dim dws As Worksheet: Set dws = wb.Sheets(DST_NAME)
Dim dfCell As Range: Set dfCell = dws.Range(DST_FIRST_CELL)
Application.ScreenUpdating = False
Dim srrg As Range, sr As Long
For Each srrg In srg.Rows
sr = sr 1
If sr > 1 Then
srg.Rows(1).Copy
dfCell.PasteSpecial Transpose:=True
srg.Rows(sr).Copy
dfCell.Offset(, dcOffset).PasteSpecial Transpose:=True
Set dfCell = dfCell.Offset(drOffset)
'Else ' it's the first row; do nothing
End If
Next srrg
Application.ScreenUpdating = True
MsgBox "Data transposed.", vbInformation
End Sub
CodePudding user response:
If I understand you correctly
Sub test()
'set the range of the header as rg variable
'count how many data under EMAIL header as cnt variable
Dim rg As Range: Set rg = Range("A1", Range("A1").End(xlToRight))
Dim cnt As Integer: cnt = Range(rg, rg.End(xlDown)).Rows.Count - 1
Dim i As Integer: Dim rslt As Range
'loop to each range with data as many as the cnt value
'prepare the result range as rslt variable
'put the value of header name to rslt range
'put the looped range value to rslt.offset(0,1)
For i = 1 To cnt
Set rslt = Range("A" & Rows.Count).End(xlUp).Offset(3, 0) _
.Resize(rg.Columns.Count, 1)
rslt.Value = Application.Transpose(rg)
rslt.Offset(0, 1).Value = Application.Transpose(rg.Offset(i, 0))
Next
End Sub
Please note, the code must be run where the sheet contains the data is active.