I'm trying to hide/replace with * the 6 middle characters of a number, but I'm not getting the desired result.

Input:

54998524154

Expected output:

54*****154

What I tried:

 const phone = "54998524154"
 phone.replace(/(?<=^[0-9]{2})([0-9]{6})/g, '*')

It returns

 54*154

I also tried replaceAll, but it returns the same result.

Edit: I'd like to achieve it using only one * like:

CodePudding user response：

If the input is always going to be 11 chars/digits, you could do something like

phone.replace(/(^\d{2})(\d{6})(\d{3}$)/g, "$1******$3");

Explanation: 3 capture groups:

1. (^\d{2}) - from the beginning of the string, select 2 digits
2. (\d{6}) - then select 6 digits
3. (\d{3}$) - Select last 3 digits

Replace pattern: "$1******$3" - First capture-group, then 6 asterisks, then 3rd capture-group.

CodePudding user response：

You can do this with the below regex.

console.log("54998524154".replace(/(\d{2})\d{6}/,"$1******"))

In fact, you can do it without regex as well.

var numStr = '54998524154';
console.log(numStr.replace(numStr.substring(2,8), "******"));