How to print a specific line in string Python?-CodePudding

So I got a string output out of a css selector while web crawling and the string has 7 lines, 6 of them are useless and I only want the 4th line.

The string is as follows:

کارکرد:
۵۰,۰۰۰
رنگ:
سفید
وضعیت بدنه:
بدون رنگ
قیمت صفر : ۳۱۵,۰۰۰,۰۰۰ تومان

Is there a way to print only the 4th line?

The crawling code:

color = driver.find_elements_by_css_selector("div[class='col']") 
for c in color:
    print(c.text)

CodePudding user response：

Yes, of course! See python documentation about list items

color = driver.find_elements_by_css_selector("div[class='col']") 
print(color[3].text)

List items are indexed, the first item has index [0], the second item has index 1 etc.

CodePudding user response：

I'm not sure if i understand the problem correctly, but assuming you have a string with multiple lines, a solution could be:

string = '''this string
exists 
on multiple
lines
so lets pick
a line
'''

def select_line(string, line_index):
    return string.splitlines()[line_index]

result = select_line(string,3)

print(result)

This function would select the number line you want (index 0 being the first line)

CodePudding user response：

If you want items one to four try this:

for idx in range(4):
    print(color[idx].text)

And if you want only 4th try this: (in python index in list start from zero.)

print(color[3].text)