String 1:

 [impro:0,grp:00,time:0xac,magic:0x00ac] CAR<7:5>|BIKE<4:0>,orig:0x8c,new:0x97

String 2:

[impro:0,grp:00,time:0xbc,magic:0x00bc] CAKE<4:0>,orig:0x0d,new:0x17

In string 1, I want to extract CAR<7:5 and BIKE<4:0,

In string 2, I want to extract CAKE<4:0

Any regex for this in Python?

CodePudding user response：

You can use \w <[^>]

• \w matches any word character (equivalent to [a-zA-Z0-9_])
• matches the previous token between one and unlimited times, as many times as possible, giving back as needed (greedy).
• < matches the character <
• [^>] Match a single character not present in the list
• matches the previous token between one and unlimited times, as many times as possible, giving back as needed (greedy)

CodePudding user response：

We can use re.findall here with the pattern (\w .*?)>:

inp = ["[impro:0,grp:00,time:0xac,magic:0x00ac] CAR<7:5>|BIKE<4:0>,orig:0x8c,new:0x97", "[impro:0,grp:00,time:0xbc,magic:0x00bc] CAKE<4:0>,orig:0x0d,new:0x17"]
for i in inp:
    matches = re.findall(r'(\w <.*?)>', i)
    print(matches)

This prints:

['CAR<7:5', 'BIKE<4:0']
['CAKE<4:0']

CodePudding user response：

In the first example, the BIKE part has no leading space but a pipe char.

A bit more precise match might be asserting either a space or pipe to the left, and match the digits separated by a colon and assert the > to the right.

(?<=[ |])[A-Z] <\d :\d (?=>)

In parts, the pattern matches:

• (?<=[ |]) Positive lookbehind, assert either a space or a pipe directly to the left
• [A-Z] Match 1 chars A-Z
• <\d :\d Match < and 1 digits betqeen :
• (?=>) Positive lookahead, assert > directly to the right

Regex demo

Or the capture group variant:

(?:[ |])([A-Z] <\d :\d)>

Regex demo