How to create a dictionary from a nested list of dictionary-CodePudding

I have a dictionary in a nested list as below. I want to create a new dictionary with keys and values from my original dictionary

my_dict= {'mc' : [[{'id': '1.185662381',
        'marketDefinition': {'bspMarket': False,
         'turnInPlayEnabled': True,
         'persistenceEnabled': True,
         'marketBaseRate': 5.0,
         'eventId': '30729399',
         'eventTypeId': '1',
         'numberOfWinners': 1,
         'bettingType': 'ODDS'}}],
    [{'id': '1.185662380',
        'marketDefinition': {'bspMarket': True,
         'turnInPlayEnabled': False,
         'persistenceEnabled': True,
         'marketBaseRate': 5.0,
         'eventId': '30729399',
         'eventTypeId': '1',
         'numberOfWinners': 1,
         'bettingType': 'ODDS'}}]]}

My expected output should look like this

new_dict = {'id':['1.185662380',1.185662381],
             bspMarket:[False,True],
            turnInPlayEnabled: [True,False]
              .....}

Here is what I have tried but It is not working rightly from my end. Any help would be greatly appreciated.

create_dict = {}
for index, arr in enumerate(my_dict):
    for arr2 in arr:
       create_dict['id'] = arr2['id]
       create_dict['bspMarket'] = arr2['marketDefinition']['bspMarket]
       create_dict['turnInPlayEnabled'] = arr2['marketDefinition']['iturnInPlayEnabled]

The above looping conditions only create a dictionary with the first element in the list. that is the element at position zero

CodePudding user response：

You're overwriting the resulting dictionary elements each time through your loop, not making lists and appending to them. You can use a defaultdict() to automatically create the lists as needed.

from collections import defaultdict

new_dict = defaultdict(list)
for l in my_dict['mc']:
    for d in l:
        new_dict['id'].append(d['id'])
        for k, v in d['marketDefinition'].items():
            new_dict[k].append(v)