I'm try to get the used storage for a ftp server through lftp.
lftp :~> open username:password@IP
lftp username@IP:~> du
897146 ./volume(sda1)
897146 .
I want to get the value of 897146
from a sh script.
This is what I got so far:
#!/bin/bash
FTP_PASS=password
FTP_HOST=IP
FTP_USER=username
LFTP=lftp
lftp << EOF
open ${FTP_USER}:${FTP_PASS}@${FTP_HOST}
FOO="$(du)"
quit
EOF
echo "$FOO"
But I'm getting
Unknown command `FOO=9544 ./logs'.
Unknown command `9636'.
CodePudding user response:
The du
command inside the FTP session will output within the lftp
command output. So to get the output of the du
command, you need to capture the output of the lftp
command inside your variable:
#!/usr/bin/env bash
FTP_PASS=password
FTP_HOST=IP
FTP_USER=username
FOO=$(lftp << EOF | filter_out_things_unrelated_to_du
open ${FTP_USER}:${FTP_PASS}@${FTP_HOST}
du
quit
EOF
)
echo "$FOO"
You will probably need to filter-out the FTP session header and MOTD from the remote FTP server and anything not related with the output of du
.