How to find the days of the week in JavaScript-CodePudding

I am trying to find the weekdays from today to Sunday. Since today is Monday I want to display the dates from Monday till Sunday, but tomorrow, I want my programme works from Tuesday to Sunday.

dateSets() {
            let firstDayOfWeek = "";
            let dates = [];
            firstDayOfWeek = new Date();
                let sunday = new Date();
                sunday.setDate(sunday.getDate() - sunday.getDay()   7);
                const diff = sunday.getDate() - firstDayOfWeek.getDate();
                dates.push(new Date());
                for (let i = 0; i < diff; i  ) {
                    dates.push(
                        new Date(firstDayOfWeek.setDate(firstDayOfWeek.getDate()   1))
                    );
                }
            return dates;
        },

And here is the other function to find the date of the week:

getDateOfWeek(week, year) {
            let simple = new Date(year, 0, 1   (week - 1) * 7);
            let dow = simple.getDay();
            let weekStart = simple;
            if (dow <= 4) weekStart.setDate(simple.getDate() - simple.getDay()   1);
            else weekStart.setDate(simple.getDate()   8 - simple.getDay());
            return weekStart;
        },

But it doesn't work that I expected, in dataset, only Monday is being displayed but not other dates and I don't understand the reason. If you can help me with this, I would be really glad. Thanks...

CodePudding user response：

This is kind of your choice but if you install NodeJS and open your folder in cmd and type in 'npm init' and 'npm I days' and open your editor and type in

var days = require('days');
console.log(days); // ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]

console will reveal all of the days of the week and if you want a specific day you can do the following

var days = require('days');
console.log(days[0]);  //Sunday

if you need help with installing NodeJS watch a YouTube video or reply to this comment I will help

CodePudding user response：

let firstDayOfWeek = "";
let dates = [];
firstDayOfWeek = new Date();
    let sunday = new Date();
    sunday.setDate(sunday.getDate() - sunday.getDay()   7);
    //const diff = sunday.getDate() - firstDayOfWeek.getDate();
    //Try this code
    var timeDiff = Math.abs(sunday.getTime() - firstDayOfWeek.getTime());
    var diff = Math.ceil(timeDiff / (1000 * 3600 * 24)); 
    dates.push(new Date());
    for (let i = 0; i < diff; i  ) {
        dates.push(
            new Date(firstDayOfWeek.setDate(firstDayOfWeek.getDate()   1))
        );
    }
return dates;

CodePudding user response：

function getWeekDates(){
  const dates = [new Date()]; // today
  const curr = new Date();
  const remDaysCount = 7-curr.getDay();
  for(let i=1; i<= remDaysCount; i  ){
    // increase current Date by 1 and set to current Date
      const nextDate = curr.setDate(curr.getDate() 1);
    dates.push(new Date(nextDate));
  }
  return dates;
}

console.log(getWeekDates());

CodePudding user response：

Your issue is here:

const diff = sunday.getDate() - firstDayOfWeek.getDate()

Currently the date is 27 Sep and next Sunday is 3 Oct so diff is -4 and the for loop test i < diff is false from the start. Consider using a loop and increment the date from today until it gets to Sunday.

function getDaysToSunday(date = new Date()) {
  let d = new Date( date);
  let result = [];
  do {
    result.push(new Date( d));
    d.setDate(d.getDate()   1);
  } while (d.getDay() != 1)
  return result;
}

console.log(getDaysToSunday().map(d=>d.toDateString()));