Using bash, an efficient way to extract a file path till a prespecified folder name, when input is a-CodePudding

I need the first three folder names from the string "/dp-ml-training/training/babyweight/trainer/notebooks/babyweight.ipynb" hence obtaining "/dp-ml-training/training/babyweight"

Or equivalently, I need the file path before the folder "/trainer" that is "/dp-ml-training/training/babyweight"

How can I achieve this in bash with sed/awk/grep/cut etc? Request your help. Thanks in Advance!

CodePudding user response：

You can use the "Parameter Expansion" of Bash.

path="your path"
echo ${path%%/trainer*}  # remove string from '/trainer' to end

CodePudding user response：

Assuming that your string is stored in the variable s, you could do a

if [[ $s =~ ^/[^/]*/[^/]*/[^/]* ]]
then
  head=${BASH_REMATCH[0]}
else
  head=$s
fi