combine each element of two lists to a tuple in Python without using itertools packet-CodePudding

I'm newbie, and I have two lists and want to combine them into a tuple, by random all possible element, without using any packet such as itertools packet. Like this example:

list1 = ["a", "b", "c"]
list2 = ["wow", 2]

and the output:

>>> new_tuple = (["a","wow"],["b","wow"],["c","wow"],["a",2],["b",2],["c",2])

Could you help me? Thank you in advance

CodePudding user response：

You could make use of itertools to make the permutation you request like the following should work for you:

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]

all_combinations = []

list1_permutations = itertools.permutations(list1, len(list2))

for each_permutation in list1_permutations:
    zipped = zip(each_permutation, list2)
    all_combinations.append(list(zipped))

print(all_combinations)

Output looks like following:

[[('a', 'wow'), ('b', 2)], [('a', 'wow'), ('c', 2)], [('b', 'wow'), ('a', 2)], [('b', 'wow'), ('c', 2)], [('c', 'wow'), ('a', 2)], [('c', 'wow'), ('b', 2)]]```

CodePudding user response：

Python3 one-liner using list comprehension

list1 = ['a', 'b', 'c']
list2 = ['wow', 2]
new_tuple = [[l1, l2] for l2 in list2 for l1 in list1]

print(new_tuple)
# [['a', 'wow'], ['b', 'wow'], ['c', 'wow'], ['a', 2], ['b', 2], ['c', 2]]

CodePudding user response：

Use itertools.product:

from itertools import product

new_tuple = tuple([a, b] for b, a in product(list2, list1))
# (['a', 'wow'], ['b', 'wow'], ['c', 'wow'], ['a', 2], ['b', 2], ['c', 2])

CodePudding user response：

import random

list1 = ["a", "b", "c"]
list2 = ["wow", 2]
new_tuple = ()
for x in (len(list1) len(list2)):
  randInt = random.randint(0, len(list1))
  randInt2 = random.randint(0, len(list2))
  new_tuple  = [list1[randInt], list2[randInt2]]

This is really simple python. Try the code out.

CodePudding user response：

What you want is basically a cartesian product. Try a list comprehension with itertools, such as:

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]

new_tuple = [x for x in itertools.product(list1, list2)]

CodePudding user response：

For converting 2 list to tuple, there is method .zip:

list(zip(list1, list2))

but it's only add elements in your case: (["a", "wow"], ["b", "2"]], so:

a = ("John", "Charles", "Mike")
b = ("Jenny", "Christy", "Monica")

tuples = []
def combineTuples(listA, listB):
  for i in range(len(listA)):
    for j in range(len(listB)):
        tuples.append((a[i], b[j]))
        
x = combineTuples(a, b)


print(tuples)

output: [('John', 'Jenny'), ('John', 'Christy'), ('John', 'Monica'), ('Charles', 'Jenny'), ('Charles', 'Christy'), ('Charles', 'Monica'), ('Mike', 'Jenny'), ('Mike', 'Christy'), ('Mike', 'Monica')]

output with your data is idnetical, but without order.

[('a', 'wow'), ('a', 2), ('b', 'wow'), ('b', 2), ('c', 'wow'), ('c', 2)]

CodePudding user response：

You can use itertools

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]
c = tuple(itertools.product(list1, list2))
print(c)