i want the count of each name on the list-CodePudding

zoo_animals = [ ]
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
for name  in zoo_animals:
    print("The number ",zoo_animals.count(name)," in the list is ",name)

it gives me:

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The number  1  in the list is  Dog
The number  1  in the list is  cat
The number  1  in the list is  fish
The number  1  in the list is  shark

What i wanted

The number  1  in the list is  Dog
The number  2  in the list is  cat
The number  3  in the list is  fish
The number  4  in the list is  shark

CodePudding user response：

If you read the documentation for the count function, it explains what it does - counts the occurrences of the parameter in the list.

You want the position / index of each item, not the count

for idx, name in enumerate(zoo_animals): 
    print(f"the animal at position {idx 1} in the list is {name}")

CodePudding user response：

List.count(item) returns how many times it appears in the list, not where. You're looking for List.index(item) (but this is 0-based, as in the first item has an index of 0 and the second item has an index of 1, so you will want to add 1 to this)

CodePudding user response：

Oh I actually found it is there something better?

zoo_animals = [ ]
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
for name  in zoo_animals:
    print("The number ", zoo_animals.index(name) 1 ," in the list is ",name)

CodePudding user response：

The count method of list returns the frequency or the number of times the provided elements has occurred in the list.

Using enumerate, we get the element and the index of it simultaneously.

zoo_animals = [ ]

zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))

for i, name in enumerate(zoo_animals):
    print("The number ", i   1," in the list is ",name)

Output:

Enter an animal = aa
Enter an animal = bb
Enter an animal = cc
Enter an animal = dd
The number  1  in the list is  aa
The number  2  in the list is  bb
The number  3  in the list is  cc
The number  4  in the list is  dd

Check the below links, to know more about enumerate(<-list name->) function

https://docs.python.org/3/library/functions.html#enumerate

https://python-reference.readthedocs.io/en/latest/docs/functions/enumerate.html

Regards,

CodePudding user response：

In your code, zoo_animals.count(name) gives the count of distinct elements in the list and not the index. You could do this instead.

for i in range(len(zoo_animals)):
    print("The number {}  in the list is {}".format(i 1,zoo_animals[i]))

Output

The number 1  in the list is dog
The number 2  in the list is cat
The number 3  in the list is fish
The number 4  in the list is shark

CodePudding user response：

zoo_animals = [ ]
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
zoo_animals.append(input("Enter an animal = "))
for name in zoo_animals:
    print("The number ",zoo_animals.index(name)   1," in the list is ",name)