What value will x have, after the following code gets executed?

char n1 = 0xF1; char n2 = 0x1F; char x = 0; x = n1 & n2;

I think it's 0, but I'm not exactly sure. What do you guys think?

CodePudding user response：

This performs the bitwise AND of each bit of the values.

To do that, you need to think of its binary form.

  0x1F   =>     0b0001 1111
& 0xF1   =>   & 0b1111 0001
------        -------------
  0x..   <=     0b.... ....

Fill in the blanks.

(There could be leading zeroes -- a char is not always 8 bits -- but it's irrelevant here because 0 AND 0 is 0.)

CodePudding user response：

The only stupid thing in this picture is all of the little minds who couldn't solve the problem without using a compiler, downvoting my question out of frustration and posting up their stupidity all over the Internet along with their incapacity, and this goes for all the users except @ikegami & Ian Abbott! If you can't solve it without a compiler, then it's best you shut up (your stupidity won't be so obvious that way)!