anyone knows a better implementation for this.. I'm trying to not assign each element in the list to a variable, instead put it directly in the for loop. Here's a snip of code to explain better.
x, y = (['a', 'b', 'c'], ['d', 'e' ,'f'])
for it in itertools.zip_longest(x, y):
print (it)
What I am trying to do is use a single liner in place of (x, y)
in the 2nd line. Since the number of lists in the List vary.
mainList = (['a', 'b', 'c'], ['d', 'e' ,'f'])
for it in itertools.zip_longest(*where I want to use the single liner*):
# The single liner should be putting passing the lists in the mainList as seperate params.
print (it)
I think this could be implemented in other loops as well.
Note: The single liner should be putting passing the lists in the mainList as seperate params.
CodePudding user response:
You could use tuple unpacking.
mainList = (['a', 'b', 'c'], ['d', 'e' ,'f'])
for it in itertools.zip_longest(*mainlist):
print (it)