Hello, how to make this program not count space as a letter and count uppercase and lowercase letter-CodePudding

how to make this program not count space as a letter and count uppercase and lowercase letters together as "one"

word = str(input())
list = []
listchcounter = []

for character  in word:
    if character not in list:
        list.append(character)
        listchcounter.append(0)
for character in word:
    for index in range(len(list)):
        if list[index] == character:
            listchcounter[index]  = 1
for index in range(len(list)):
    print("'"   list[index]   "'",'appears',listchcounter[index],'times')

CodePudding user response：

Only changes are in line 1 the .lower() behind the input. And in line 6 the and character != ' ' . Then the code already works fine.

word = str(input().lower())
list = []
listchcounter = []

for character  in word:
    if character not in list and character != ' ':
        list.append(character)
        listchcounter.append(0)
for character in word:
    for index in range(len(list)):
        if list[index] == character:
            listchcounter[index]  = 1
for index in range(len(list)):
    print("'"   list[index]   "'",'appears',listchcounter[index],'times')

CodePudding user response：

The comments by @dimitry contain the basic ways to address your stated question.

To exclude spaces you want to filter them out with a if character != ' '.

To treat upper and lower cased letters as the same, you want to convert all characters to lowercase via character = character.lower().

Let's put these together:

word = "foOtball Timeout"
letters = [letter.lower() for letter in word if letter != " "]
print(letters )

Giving us:

['f', 'o', 'o', 't', 'b', 'a', 'l', 'l', 't', 'i', 'm', 'e', 'o', 'u', 't']

Now we can count them. I would personally use collections.Counter() for this, but it is easy enough to do it by hand.

letter_counts = {}
for letter in letters:
    letter_counts[letter] = letter_counts.get(letter, 0)   1
print(letter_counts )

Giving us the crux of what is required:

{'f': 1, 'o': 3, 't': 3, 'b': 1, 'a': 1, 'l': 2, 'i': 1, 'm': 1, 'e': 1, 'u': 1}

Now all that is left is to print the results out nicely:

for letter, count in letter_counts.items():
    print(f"The letter \"{letter}\" appears {count} time(s) in \"{word}\"")

Giving:

The letter "f" appears 1 time(s) in "foOtball Timeout"
The letter "o" appears 3 time(s) in "foOtball Timeout"
The letter "t" appears 3 time(s) in "foOtball Timeout"
The letter "b" appears 1 time(s) in "foOtball Timeout"
The letter "a" appears 1 time(s) in "foOtball Timeout"
The letter "l" appears 2 time(s) in "foOtball Timeout"
The letter "i" appears 1 time(s) in "foOtball Timeout"
The letter "m" appears 1 time(s) in "foOtball Timeout"
The letter "e" appears 1 time(s) in "foOtball Timeout"
The letter "u" appears 1 time(s) in "foOtball Timeout"

Full code:

word = "foOtball Timeout"
letter_counts = {}
for letter in [letter.lower() for letter in word if letter != " "]:
    letter_counts[letter] = letter_counts.get(letter, 0)   1
for letter, count in letter_counts.items():
    print(f"The letter \"{letter}\" appears {count} time(s) in \"{word}\"")

or if you wanted to use collections.Counter:

import collections
word = "foOtball Timeout"
letter_counts = collections.Counter(l.lower() for l in word if l != " ")
for letter, count in letter_counts.items():
    print(f"The letter \"{letter}\" appears {count} time(s) in \"{word}\"")