check if number has neighbourhood in list python-CodePudding

I should append a number x in a list called y if in y there are not number that are in the neighbourhood of x. For example, if I have:y = [1, 1.5, 1.7, 2.1, 3] i need to append a number that is not in the range /-0.1 of the number in the list. So I will append x = 3.2 but not append x =3.05

CodePudding user response：

I don't know if the range condition applies to all the list elements or only the last one, here's the example of both:

def foo(lst:list, value, dif=0.1):
    clos = min(lst, key=lambda lst : abs(lst - value))
    if abs(clos - value) > dif:
        lst.append(value)
    return lst
foo(y, 3.2)
Output: [1, 1.5, 1.7, 2.1, 3, 3.2]

Or only to last element:

def foo(lst:list, value, dif=0.1):
    if abs(value - lst[-1]) > dif:
        lst.append(value)
    return lst

CodePudding user response：

What you are looking for is probably np.isclose

# For x = 3.2
>>> ~np.isclose(y, x, atol=0.1).any()
True

# For x = 3.05
>>> ~np.isclose(y, x, atol=0.1).any()
False