In Kotlin, can I have two random values with the second one omitting the first random number?-CodePudding

Here is what I am trying to say:

val firstNumbers = (1..69).random()
val secondNumbers = (1..69).random()

I would like the secondNumbers to omit the random number picked in firstNumbers

CodePudding user response：

If you're just generating two numbers, what you could do is lower the upper bound for secondNumbers down to 68, then add 1 if it's greater than or equal to the first number. This will ensure an even distribution:

val firstNumber = (1..69).random()
var secondNumber = (1..68).random()
if (secondNumber >= firstNumber) {
    secondNumber  = 1
}

CodePudding user response：

Another approach could be to find one number in range 1..69, remove that number from the range and find the second one.

val first = (1..69).random()
val second = ((1..69) - first).random()