What method uses the least memory to generate a range of numbers as a list?-CodePudding

When I run the following code to generate a list made of a range of numbers from 0 till 999 999 999. It raises a MemoryError. What other way can I use to generate the same list but wont use up that much memory?

# Generate list
numbers = list(range(0,999999999))

# Add leading zeros
numbers = [str(x).zfill(9) for x in numbers]

CodePudding user response：

Use a generator:

numbers = (str(i).zfill(9) for i in range(999999999))

CodePudding user response：

Using a generator:

def generator(n):
    i = 0
    while i < n:
        yield str(i).zfill(9)
        i  = 1

Usage:

for i in generator(5):
    print(i)

Or, to create a list:

[i for i in generator(5)]