Passing many variables as one variable in python-CodePudding

I have a list of variables that I want to send to my function. (so the function works based on the values on those variables).

One way is to pass each variable separately in the function like this:

def my_function(var1, var2, var3, var4, ..., varn):
   output = var1   var2   var3   var4   ....   varn

However, I wonder if I can write such a thing:

def my_function(parameters):
    output = parameters.var1   parameters.var2   ...   parameters.varn

That is, somehow is there any way to wrap all variables in one variable, and then call them like this?

I know the above python codes are not correct, I just want to express my question.

Thanks in advance

CodePudding user response：

There are many options. You have to determine which way fits your case.

Option 1. Getting multiple arguments by a single asterisk

def my_function(*args):
    output = sum(args)

    # SAME WITH
    # output = args[0]   args[1]   ...   args[n]
    #
    # PASSING ARGUMENTS EXAMPLE
    # my_function(10, 20, 10, 50)

Option 2. Getting keyword arguments by double asterisk

def my_function(**kwargs):
    output = sum(kwargs.values())
    
    # SAME WITH
    # output = kwargs["var0"]   kwargs["var1"]   ...   kwargs["varn"]
    #
    # PASSING ARGUMENTS EXAMPLE
    # my_function(var0=10, var1=20, var2=15)

Option 3. Getting an argument as a list

def my_function(list_arg):
    output = sum(list_arg)

    # SAME WITH
    # output = list_arg[0]   list_arg[1]   ...   list_arg[n]
    #
    # PASSING ARGUMENTS EXAMPLE
    # my_function([1, 10, 3, -10])

Option 4. Getting an argument as a dictionary

def my_function(dict_arg):
    output = sum(dict_arg.values())

    # SAME WITH
    # output = kwargs["var0"]   kwargs["var1"]   ...   kwargs["varn"]
    #
    # PASSING ARGUMENTS EXAMPLE
    # my_function({"var0":5, "var1":10, "var2":3})