Regex for negative number with leading zeros and words with apastrophe-CodePudding

hey I need a regex that removes the leadings zeros. right now I am using this code . it does work it just doesn't keep the negative symbol.

String regex = "^ (?!$)";
String numbers = txaTexte.getText().replaceAll(regex, ")

after that I split numbers so it puts the numbers in a array.

input :
-0005
0003
-87

output :
-5
3
-87

I was also wondering what regex I could use to get this. the words before the arrow are input and after is the output the text is in french. And right now I am using this it works but not with the apostrophe.

String [] tab = txaTexte.getText().split("(?:(?<![a-zA-Z])'|'(?![a-zA-Z])|[^a-zA-Z']) ")

Un beau JOUR. —> Un/beau/JOUR

La boîte crânienne —> La/boîte/crânienne

C’était mieux aujourd’hui —> C’/était/mieux/aujourd’hui

qu’autrefois —> qu’/autrefois

D’hier jusqu’à demain! —> D’/hier/jusqu’/à/demain

Dans mon sous-sol—> Dans/mon/sous-sol

CodePudding user response：

You might capture an optional hyphen, then match 1 more times a zero and 1 capture 1 or more digits in group 2 starting with a digit 1-9

^(-?)0 ([1-9]\d*)$

^ Start of string
(-?) Capture group 1, match optional hyphen
0 Match 0 zeroes
([1-9]\d*) Capture group 2, match 1 digits starting with a digit 1-9
$ End of string

See a regex demo.

In the replacement use group 1 and group 2.

String regex = "^(-?)0 ([1-9]\\d*)$";
String text = "-0005";
String numbers = txaTexte.getText().replaceAll(regex, "$1$2");

CodePudding user response：

Here is one way. This preserves the sign.

capture the optional sign.
check for 0 or more leading zeros
followed by 1 or more digits.

String regex = "^([ -])?0*(\\d )";
String [] data = {"-1415", " 2924", "-0000123", "000322", " 000023"};
for (String num : data) {
    String after = num.replaceAll(regex, "$1$2");
    System.out.printf("%8s --> %s%n", num , after);
}

prints

   -1415 --> -1415
    2924 -->  2924
-0000123 --> -123
  000322 --> 322
  000023 -->  23