The program only works when the no. of elements is 2 if it is more than 2 it doesn't work.

#Selection Sort
L = []
n = int(input('Enter the number of elements\t:'))
for i in range(n):
    item = int(input('Enter item\t:'))
    L.append(item)
    print('List\t:')
    for i in range(n-1):
        for j in range ((i 1),n-1):
            if (L[j]<L[i]):
                (L[j],L[i]) = (L[i],L[j])
print(L)

output1 output2

CodePudding user response：

L = []
n = int(input('Enter the number of elements\t:'))
for i in range(n):
    item = int(input('Enter item\t:'))
    L.append(item)
    print('List\t:')
for i in range(n):
    #First loop from 0 to n-1
    for k in range(n-1):
        #second loop from 1 to n
        for j in range ((k 1),n):
            if (L[j]<L[k]):
                (L[j],L[k]) = (L[k],L[j])

print(L)

input

Enter item      :5
List    :
Enter item      :2
List    :
Enter item      :3
List    :
Enter item      :1

output

[1, 2, 3, 5]

CodePudding user response：

try this

enter code here
#Declare variable for selection sort
L = []
n = int(input('Enter the number of elements\t:'))
#iterate for add values
for i in range(n):
    item = int(input('Enter item\t:'))
    L.append(item)
    print('List\t:')
#iterate for select minimun value and swap value in the array    
for i in range(len(L)):
    # Find the minimum element in remaining 
    # unsorted array
    min_idx = i
    for j in range(i 1, len(L)):
        if L[min_idx] > L[j]:
            min_idx = j
              
    # Swap the found minimum element with 
    # the first element        
    L[i], L[min_idx] = L[min_idx], L[i]
print(L)

CodePudding user response：

Code:

#Selection Sort
L = []
n = int(input('Enter the number of elements\t:'))
for i in range(n):
    item = int(input('Enter item\t:'))
    L.append(item)
print('List\t:')
for i in range(n-1):
    for j in range ((i 1),n):
        if (L[j]<L[i]):
            (L[j],L[i]) = (L[i],L[j])
print(L)

Output:

Here