Issues clicking a button (element not interactable) in Selenium using Python-CodePudding

I have a problem clicking the second button because i get this error message:

selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable

htlm button:

<button  type="button" 
    <span  aria-hidden="true"></span>
    <span > </span>

<button  type="button" 
    <span  aria-hidden="true"></span>
    <span >-</span>

my code:

button = driver.find_element_by_css_selector('div.amount-control > button.btn.btn-primary.btn-fab > span.mdi.mdi-plus')
button.click()

what my code does is locating the second button, the problem is I have to locate <span aria-hidden="true"></span> to diferenciate both buttons but i think i have to click <button type="button" not the span because it's not interactable.

How can i click the <button> and not the span after locating the span.

CodePudding user response：

You can receive the parent node of an element by the following.

button = driver.find_element_by_css_selector('div.amount-control > button.btn.btn-primary.btn-fab > span.mdi.mdi-plus')
actual_button = button.find_element_by_xpath('./..')

Furthermore, I would recommend you to use the following script to click an element in selenium, since selenium often has problems with clicking on elements.

try:
    element = driver.find_element(By.XPATH, path)
    driver.execute_script("arguments[0].click();", element)
except Exception as e:
    print(e)

Note that you just have to replace the path variable with your xpath.

CodePudding user response：

Your elements are not closed correctly. The </button> closing tag is missing in both cases. Please change your code to this:

<button  type="button" 
    <span  aria-hidden="true"></span>
    <span > </span>
</button>

<button  type="button" 
    <span  aria-hidden="true"></span>
</button>