I have list of patterns and I need to return that pattern if that is present in the given string else return None. I tried with the below code using re module , but I am getting only null in "matches" (when I tried to print matches). Completely new to corepython and regex,kindly help
import re
patterns_lst=['10_TEST_Comments','10_TEST_Posts','10_TEST_Likes']
def get_matching pattern(filename):
for pattern in patterns_lst:
matches = re.(pattern,filename)
if matches:
return matches
else:
return None
print(get_matching pattern("6179504_10_TEST_Comments_22-Nov-2021_22-Nov-2021.xlsx"))
CodePudding user response:
I have made some changes to your function:
def get_matching_pattern(filename): ## Function name changed
for pattern in patterns_lst:
match = re.search(pattern, filename) ## Use re.search method
if match: ## Correct the indentation of if condition
return match ## You also don't need an else statement
Output:
>>> print(get_matching_pattern("6179504_10_TEST_Comments_22-Nov-2021_22-Nov-2021.xlsx"))
<re.Match object; span=(8, 24), match='10_TEST_Comments'>