Is it O(n) or O(n*n)?
The loop runs approximately n*n times but the loop variable is only one.
I'm confused whether it's O(n) algorithm I think it should be O(n*n) but gfg says it's O(n)
Can anybody help me with the answer??
int j=0;
for(int i=1; i<=n; )
{
if(j<i)
{
j ;
continue;
}
if(j==i)
{
i ;
j=0;
}
}
CodePudding user response:
This is O(1 2 ... n), that is the arithmetic progression, the sum is O(n * (n 1) / 2) ≈ O(n²).
CodePudding user response:
I think this loop runs 1 2 ... n times because j
needs to be incremented i - 1
times as i
grows, and i
grows n
times. That gives a time complexity of O(n^2).