I want to print the following string:
1234567890
as follows:
123
456
789
0
How can I do this in Python?
CodePudding user response:
You could use re.findall
here:
inp = '1234567890'
output = '\n'.join(re.findall(r'.{1,3}', inp))
print(output)
This prints:
123
456
789
0
CodePudding user response:
try this:
x = "1234567890"
n = 3
y = list([x[i:i n] for i in range(0, len(x), n)])
for chunk in y:
print(chunk)