Python function that returns the first location as index in which the strings differ. If the strings-CodePudding

I am writing a python program that uses a function, the function name I have for example is first_difference(str1, str2) that accepts two strings as parameters and returns the first location in which the strings differ. If the strings are identical, it should return -1. However, I could not get the index of the character. What I have right now is just the character which is the first location of difference, does anyone know a good way to get the index number of the character in the loop?

def first_difference(str1, str2):
    """
    Returns the first location in which the strings differ.
    If the strings are identical, it should return -1.
    """
    if str1 == str2:
        return -1
    else:
        for str1, str2 in zip(str1, str2):
            if str1 != str2:
                return str1


string1 = input("Enter first string:")
string2 = input("Enter second string:")
print(first_difference(string1, string2))

TEST CASE:

INPUT

Enter first string: python

Enter second string: cython

OUTPUT

Enter first string: python

Enter second string: cython

So instead of 'p', the goal is to get the index number of p which is at index 0.

CodePudding user response：

You just need an index counter as follows:

s1 = 'abc'
s2 = 'abcd'

def first_difference(str1, str2):
    if str1 == str2:
        return -1
    i = 0
    for a, b in zip(str1, str2):
        if a != b:
            break
        i  = 1
    return i

print(first_difference(s1, s2))