Change datetime weekday without going back in time-CodePudding

How do I set the weekday for the provided datetime object without looping back in time?

This is how I first did it

now = dt.datetime.now() # February 18
target_weekday = 2 # Wednesday next week
future = ((now - dt.timedelta(days=now.weekday()))   dt.timedelta(days=target_weekday))

This outputs this week's wednesday which is February 16 (In the past) What I want is for it to output next week's wednesday, not all the time though, it only has to move to next week if the provided target_weekday is in the past. But if the weekday is let's say 5, then it would just add an extra day

CodePudding user response：

It can be checked if the target weekday is in the past or future and add days according to that in timedelta

now = dt.datetime.now()
target_weekday = 5
result = now   dt.timedelta(
  days=(7 - target_weekday if now.weekday() > target_weekday else target_weekday - now.weekday()))
print(result)

CodePudding user response：

So I was able to figure out a solution that works all the time

def construct_next(weekday: int, datetime: dt.datetime) -> dt.datetime:
    if weekday == datetime.weekday():
        return datetime   dt.timedelta(days=7)
    elif weekday > datetime.weekday():
        return datetime   dt.timedelta(days=weekday - datetime.weekday())
    return ((datetime - dt.timedelta(days=datetime.weekday()))   dt.timedelta(days=weekday   7))