addaddress.setOnClickListener {
            val pincoder = zipcode.text.toString().trim()
            val pinCodeList = listOf("201014", "201301")
            val productsRef =  FirebaseFirestore.getInstance().collection("Pincode")
                .document("zipcollect").collection("zipcodes")
            productsRef.whereArrayContainsAny("pin_code", pinCodeList).get().addOnCompleteListener {
                if (pincoder.equals(it.isSuccessful.toString()) == 0)
                {
                    for (document in it.result!!) {
                        Log.d(TAG, document.id   " => "   document.data)
                        Toast.makeText(this,"We Deliver Here!", Toast.LENGTH_SHORT).show()
                    }
                }
                else {
                    Toast.makeText(this,"We Don't Deliver Here!", Toast.LENGTH_SHORT).show()
                }
            }

firebase structure

Here's a screenshot of data stored in firestore

CodePudding user response：

You cannot tell Firestore, hey Firestore return me all documents where the pin_code array contains all elements of pinCodeList.

To solve this, you might consider using a Map rather than an array. Your document should look like this:"

pin_codes
   |
   --- code_one: 201014
   |
   --- code_two: 303007
   |
   --- code_three: 201301

And then perform a separate in query for each code, that looks like this:

val firstCodeQuery = productsRef.whereIn("pin_codes.code_one", Arrays.asList("201014", "201301"))
val firstTask = firstCodeQuery.get()

Do the same for the second and the third query. If one of the values in the List doesn't exist in the Map, doesn't exist in Map, then simply stop querying. If all are present, simply collect the results on the client using my answer from the following post:

• Firestore - Merging two queries locally

Alternatively, you can perform a whereArrayContains operation for each element in the list.

CodePudding user response：

whereArrayContainsAny can be perform on collection and return list of documents and you are tring to get field.

array-contains-any

Use the array-contains-any operator to combine up to 10 array-contains clauses on the same field with a logical OR. An array-contains-any query returns documents where the given field is an array that contains one or more of the comparison values:

You can read here for more detail about array-contains-any You can perform your action like this

val pincoder = zipcode.text.toString().trim()
FirebaseFirestore.getInstance()
    .collection("Pincode")
    .document("zipcollect")
    .collection("zipcodes")
    .document("Am0U....<Fill your doc ref>").get()
    .addOnCompleteListener {
        it.let {
            if (it.isSuccessful && it.result != null) {
                val pinCodeList = it.result["pin_code"] as List<String>
                if(pinCodeList.contains(pincoder)){
                    Toast.makeText(this,"We Deliver Here!", Toast.LENGTH_SHORT).show()
                }else{
                    Toast.makeText(this,"We Don't Deliver Here!", Toast.LENGTH_SHORT).show()
                }
            }
        }
    }
    .addOnFailureListener {
        AppLog.e("===========", "Data fail "   it)
    }