I have two arrays of users which have the same iDs. I want to merge them based on the updatedAt property that each user has. The user who has newer updatedAt property has priority.
const users1 = [
{ id: 1, name: 'user1', childUsers: [2], updatedAt: '2022-02-23T00:00:00.000Z' },
{ id: 2, name: 'user2', childUsers: [3, 4], updatedAt: '2022-01-26T00:00:00.000Z' },
{ id: 3, name: 'user3', childUsers: [2, 3], updatedAt: '2022-02-24T00:00:00.000Z' },
{ id: 4, name: 'user4', childUsers: [2, 4], updatedAt: '2022-02-26T00:00:00.000Z' },
]
const users2 = [
{ id: 1, name: 'user1', childUsers: [2], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 2, name: 'user2.1', childUsers: [3, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
{ id: 3, name: 'user3', childUsers: [2, 3], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 4, name: 'user4.1', childUsers: [2, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
]
Output should be
const mergedUsers = [
{ id: 1, name: 'user1', childUsers: [2], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 2, name: 'user2.1', childUsers: [3, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
{ id: 3, name: 'user3', childUsers: [2, 3], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 4, name: 'user4.1', childUsers: [2, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
]
CodePudding user response:
You can use Array.reduce()
to group users by id, replacing any entry with a newer updatedAt
property.
Once we have the grouped users, we can use Object.values()
to get the desired result:
const users1 = [
{ id: 1, name: 'user1', childUsers: [2], updatedAt: '2022-02-23T00:00:00.000Z' },
{ id: 2, name: 'user2', childUsers: [3, 4], updatedAt: '2022-01-26T00:00:00.000Z' },
{ id: 3, name: 'user3', childUsers: [2, 3], updatedAt: '2022-02-24T00:00:00.000Z' },
{ id: 4, name: 'user4', childUsers: [2, 4], updatedAt: '2022-02-26T00:00:00.000Z' },
]
const users2 = [
{ id: 1, name: 'user1', childUsers: [2], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 2, name: 'user2.1', childUsers: [3, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
{ id: 3, name: 'user3', childUsers: [2, 3], updatedAt: '2022-02-26T00:00:00.000Z' },
{ id: 4, name: 'user4.1', childUsers: [2, 4], updatedAt: '2022-02-27T00:00:00.000Z' },
]
const result = Object.values([...users1, ...users2].reduce((acc, user) => {
// Entry either does not exist or has an older updatedAt property
if (!acc[user.id] || (user.updatedAt > acc[user.id].updatedAt)) {
acc[user.id] = user;
}
return acc;
}, {}))
console.log('Result:', result)
CodePudding user response:
You want to compare each user in the first array with its similar one from the second array and choose the one with the higher updatedAt date.
const users1 = [...];
const users2 = [...];
const merged = users1.map((user1) => {
// loop through the users1 array
const duplicateUser = users2.find((user2) => user1.id === user2.id);
// if a similar user was found
if (duplicateUser) {
// compare and return the user with the newer updatedAt date
return new Date(duplicateUser.updatedAt) > new Date(user1.updatedAt)
? duplicateUser
: user1;
}
return user1; // in the case of no duplicates
});
console.log(merged);