Check if key is present in list of dictionaries and if true return dictionary index in list-CodePudding

I have a list of dictionaries and I'm trying to check if there is a key in each dictionary called 'tag' with a value of 'staging automator'. If this is true then create a new list with just those dictionaries.

    "entry": [
    {
        "@location": "vsys",
        "@name": "reactor-test",
        "@vsys": "vsys1",
        "dynamic": {
            "filter": "'reactor' or 'ACI-Reactor_epg'"
        },
        "tag": {
            "member": [
                "reactor"
            ]
        }
    },
    {
        "@location": "vsys",
        "@name": "Customer Access",
        "@vsys": "vsys1",
        "description": "Allowed addresses for external customers",
        "static": {
            "member": [
                "GG-sub"
            ]
        }
    },
    {
        "@location": "vsys",
        "@name": "test-dynamic-group",
        "@vsys": "vsys1",
        "dynamic": {
            "filter": "'staging-automator'"
        }
    },
    {
        "@location": "vsys",
        "@name": "MyDynamicGroup",
        "@vsys": "vsys1",
        "description": "I edited this via postman because I'm cool.",
        "dynamic": {
            "filter": "staging-automator"
        },
        "tag": {
            "member": [
                "staging-automator"
            ]
        }
    }
]

So far I've come up with this which will tell me which dictionaries in the list contain what I'm looking for:

for item in myList:
    if "tag" in item.keys():
        if item["tag"]["member"][0] == "staging-automator":
            print("True")
        else:
            print("False")
    else:
        print("False")

But I'm stuck with how to then grab that dictionary out of the list.

CodePudding user response：

Hope it helps:

new_list = []
for item in your_dictionaries:
    if "tag" in item.keys():
        if item["tag"]["member"][0] == "staging-automator":
            new_list.append(item)
print(new_list)

CodePudding user response：

Inside the loop you already have your desired dictionary!

Where you are checking for the staging-automator, the item variable is your required thing; just append it to a new list.

Here's how it can be done

new_list = []
        
for item in myList:
    if "tag" in item:
        if item["tag"]["member"][0] == "staging-automator":
            print("True")
            new_list.append(item)
            continue
    print("False")

print(new_list)

CodePudding user response：

# a is the list of dict you have provided 
# Code by @Rishi
tag_list=[]
for i in a:
      if "tag" in i:
            if i["tag"]['member'][0]=="staging-automator":
                  tag_list.append(i)

Or use list comprehension:

b=[i for i in a if "tag" in i if i["tag"]['member'][0]=="staging-automator"]
print(b)

Explanation:

Just readed the items in the list,
checked if "tag" is present in the item,
if preset then again checked if tags:member's attributes is "staging-automator",
if that too is true then, i have appended it to the tag_list.

in searches if the given value is present in any data type for example in string, list, tuple ect.

List comprehension would be useful if you are having a large dict, as its faster than the normal for-loop.

CodePudding user response：

Use a filter instead of a loop.

def check_item(item):
    return "tag" in item and item["tag"]["member"][0] == "staging-automator"

list(filter(check_item, myList))