How not to execute functions when they are set as values in dictionary-CodePudding

I tried to execute this part of code:

def func():
    print 'function is being called'

mapp=dict{'first': 'value_1','second':func()}
   

print mapp.get('first')

I expected to see output as 'value_1', but the function is also getting executed even though I am not explicitly calling it. Output: enter image description here

How to make this dictionary so that, the function will not be executed when not called explicitly.

CodePudding user response：

func() will call the function. If you want to get the function as a first-class object, then just use func. Example:

mapp = {'first': 'value_1', 'second': func}

CodePudding user response：

Put the function name in the dictionary without the parentheses, just the function name: mapp=dict{'first': 'value_1', second':func}.

CodePudding user response：

def func():
    print('function is being called')


def func_2(msg='No comment'):
    print(msg)


mapp = {'first': 'value_1', 'second': func, 'third': func_2, 'fourth': func_2}

print(mapp.get('first'))
mapp.get('second')()
mapp.get('third')()
mapp.get('fourth')('Yes, I have a lot to say')

Output

value_1
function is being called
No comment
Yes, I have a lot to say