Given a byte array buff
of length n
:
unsigned char buff[n] = "....." // len n
I want to delete m
characters at position pos
,
0 < pos, m, pos m < n
I tried using memmove
:
memmove(buff pos, buff pos m, n - (pos m) 1);
But this doesn't work for byte array as we don't have '\0' terminator for this buff (but we know its length)
How do I delete bytes in between? Anyone please help
Edit: Sample input,
Pos Data
0000 03 00 02 ef 02 f0 80 64 00 08 03 eb 70 82 e0 40
0010 00 ff 30 00 00 00 00 b3 47 43 00 00 00 00 00 00
0020 00 1e 00 c4 00 00 00 00 00 00 00 44 00 65 00 66
0030 00 61 00 75 00 6c 00 74 00 41 00 6c 00 74 00 53
Say I want to delete the highlighted bytes from packet.
New paket,
Pos Data
0000 03 00 02 ef 02 f0 80 64 00 08 03 00 00 00 00 00
0010 00 00 44 00 65 00 66 00 61 00 75 00 6c 00 74 00
0020 41 00 6c 00 74 00 53
CodePudding user response:
This would erase m
chars in an array without terminating null character.
int main()
{
int pos = 1, m = 3;
unsigned char arr[8] = {1,2,3,4,5,6,7,8};
memmove(arr pos, arr pos m, sizeof(arr)/sizeof(arr[0]) - pos - m);
// if required to zero-out the remaining elements
memset(arr pos m 1, 0, sizeof(arr)/sizeof(arr[0]) - pos - m - 1);
for (int i = 0; i < sizeof(arr)/sizeof(arr[0]); i )
printf("%hhu ", arr[i]);
return 0;
}
Output: 1 5 6 7 8 0 0 0
CodePudding user response:
You probably want something like this:
#include <stdio.h>
#include <string.h>
void Display(const char buff[], int nb)
{
for (int i = 0; i < nb; i )
printf("%d ", buff[i]);
printf("\n");
}
int main()
{
unsigned char buff[20] = { 0,1,2,3,4,5 };
// buff has room for 20 elements
int nbelements = 6; // but there are only 6 meaningful elements
Display(buff, nbelements);
int pos = 1; // delete from element 1
int nbtodelete = 2; // delete 2 elements
memmove(buff pos, buff pos nbtodelete, nbelements - pos - 1);
nbelements -= nbtodelete;
Display(buff, nbelements);
}
Output:
0 1 2 3 4 5
0 3 4 5
It's pretty self explanatory.