Write a python3 function sqr( n ) that returns the square of its numeric parameter n.

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Can you reply this question? I can't Understand this problem

CodePudding user response：

you need to create a function, which takes a number n as input and the
returns/outputs the square of that number i.e n2 for example: sqr(2) will return/result as = 4

CodePudding user response：

def sqr(n):
    return n * n

As easy as that