Grab the second number and the word after it using regexp-CodePudding

I have a string:

str = "1 - hello world 1234 abc 5678 def"

I want to grab 1234 abc from the string.

My current implementation str[/\d \s*\D*$/] only grabs the last number with the word.

CodePudding user response：

You can use

str[/\d \D (\d \s*\w )/, 1]
str[/\d \D \K\d \s*\w /]

Here, only the first regex match is searched for. Details:

\d - one or more digits
\D - one or more non-digits
(\d \s*\w ) - Group 1: one or more digits, zero or more whitespaces, and one or more word chars
\K - match reset operator that discards all text matched so far.

NOTE:

If a "word" is a chunk of non-whitespace chars, replace \w with \S
If you want to support float values (numbers with fractional parts), you will need to replace \d with \d*\.?\d or \d (?:\.\d )? patterns.

Here is a Ruby test:

str = "1 - hello world 1234 abc 5678 def"
puts str[/\d \D (\d \s*\w )/, 1]
# => 1234 abc
puts str[/\d \D \K\d \s*\w /]
# => 1234 abc