I'm a bit surprised I'm having trouble finding this online, but I can't seem to find an example of how to do this in a React functional component. I have a React component that I would like to render when I click a button. Right now the function fires and I can see my console.log firing, however the component isn't rendering. My first guess was that it won't render because React doesn't know to update the view, however I added boolean via useState and it still won't render. What am I doing wrong?
Below is the relevant code. How can I get the component in addSection to render?
const FormGroup = ({index}) => {
const [additionalSection, setAdditionalSection] = useState(false);
const addSection = form => {
setAdditionalSection(true);
console.log('form', form);
return additionalSection && (
<div key={form.prop}>
<p>This should render</p>
<AdditiveSection
form={form}
register={register}
errors={errors}
/>
</div>
);
};
...
return (
...
<FormAdd>
<LinkButton
type="button"
onClick={() => addSection(form)}
>
span className="button--small">{form.button}</span>
</LinkButton>
</FormAdd>
);
CodePudding user response:
You should change your state (or a prop in your useEffect dependency array in case you had one) in order to force a rerender. In this case:
setAdditionalSection(prevState=>!prevState);
CodePudding user response:
A state change like the one you are calling, will trigger a re-render.
But all html to be rendered must be included in the functional components return statement. The elements you want to render can be conditionally rendered like this:
const FormGroup = ({index}) => {
const [additionalSection, setAdditionalSection] = useState(false);
const addSection = form => {
setAdditionalSection(true);
console.log('form', form);
};
...
return (
...
<FormAdd>
<LinkButton
type="button"
onClick={() => addSection(form)}
>
<span className="button--small">{form.button}</span>
</LinkButton>
{additionalSection &&
<div key={form.prop}>
<p>This should render</p>
<AdditiveSection
form={form}
register={register}
errors={errors}
/>
</div>
}
</FormAdd>
);