Get a number as many as the user inputed-CodePudding

I have a task to make an output program like this

if input : 5
then output : 2,6,10,14,18

Output must as many of total number as the input

My previous code like this

n = 5
num = 2
i = 1

while i <= n:
  if num % 2 == 0:
    if num % 4 != 0:
      print(num)
  i = i 1
  num = num 1

But my output was just 2 numbers, i should get 5 numbers.

2,6

Can anyone help me?

CodePudding user response：

Put the i 1 under the second if condition

if num % 4 != 0:
  print(num)
  i = i   1

CodePudding user response：

As you can see your output is following the Arithmetic progression

#### first number
a = 2 
#### diffrence between the seq numbers
d = 4
#### number of terms in sequence
n = 5 

### running loop n times
### a   (n-1) * d ( geeting the nth didgit in AP `enter code here`)

for i in range(1, n 1):
    print(2   (i-1)*d , end=',')