How can i trim just specific characters from my string?-CodePudding

I have the following array

const re = '    ';
var arr  = ['\t', '\n3\t3', '\n\t', '\n3\t3', '\n2\t', '\n\t2', '\n']

i need to trim the \t and \n characters from strings. So when i try

for(let i = 0;i < arr.length;i  ) {
let row = arr[i].split(re);
console.log(row);
}

i get

['', '']
['\n3', '3']
['\n', '']
['\n3', '3']
['\n2', '']
['\n', '2']
['\n']

i can't find a way to remove the \n charactes here when i get to this point so when i have just \n as element then it should be replaced with '' - empty string.

If the character includes other things inside for example

\n2

so \n before or after a number then i shold get just the number and to have just 2 inside

How can i replace this \n cahracters

CodePudding user response：

Reference: Here

It is not good practice to do with split method. You can use replace method instead.

Here is example what you want to do:

var someText = "Here's some text.\n It has some line breaks that will be removed \r using Javascript.\r\n";

someText = someText.replace(/(\r\n|\n|\r)/gm,"");

console.log(someText);

You can edit your replace method what you want to use in it.

Note: "/(\r\n|\n|\r)/gm" this is a regex.

CodePudding user response：

You may do a regex replacement on [\t\n] to remove these characters:

var arr = ['\t', '\n3\t3', '\n\t', '\n3\t3', '\n2\t', '\n\t2', '\n'];
var output = arr.map(x => x.replace(/[\t\n] /g, ""));
console.log(output);

Note that if there could be other whitespace characters which you also want to remove, just do a regex replacement on \s .

CodePudding user response：

You can just use String.prototype.trim(). It cleans \n and \t as well. It is only for trimming. It will not remove characters in the middle of the string. Example:

const arr = ['\t', '\n3\t3', '\n\t', '\n3\t3', '\n2\t', '\n\t2', '\n'];
const newArr = arr.map(val => val.trim());

CodePudding user response：

Use replace() function of string combined with map() function of array. It will look like this

arr.map(c => c.replace(/(\n|\t)/gi, ''))

Output will be:

[ '', '33', '', '33', '2', '2', '' ]

If you don't want to see empty strings in array you can just filter them with .filter(Boolean)

arr.map(c => c.replace(/(\n|\t)/gi, '')).filter(Boolean)

Output will be:

[ '33', '33', '2', '2' ]

CodePudding user response：

You can use a simple replace function:

var arr  = ['\t', '\n3\t3', '\n\t', '\n3\t3', '\n2\t', '\n\t2', '\n']
var row="";
var newArr=[];

for(i=0; i<arr.length; i  ){
    row = parseInt(arr[i].replace('\tn',""));
    if(isNaN(row) === false){newArr.push(row)}
}

console.log(newArr);

First replace("\,t,n") your characters, then parseInt() to convert remaining string-numbers to integers, lastly distinguish those numbers and push() them to a new array.