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Applying custom function to a list of DFs, taking another list as an input - R

Time:04-19

I have a list of dfs and a list of annual budgets. Each df represents one business year, and each budget represents a total spend for that year.

# the business year starts from Feb and ends in Jan.
# the budget column is first populated with the % of annual budget allocation

df <- data.frame(monthly_budget=c(0.06, 0.13, 0.07, 0.06, 0.1, 0.06, 0.06, 0.09, 0.06, 0.06, 0.1, 0.15),
          month=month.abb[c(2:12, 1)])

# dfs for 3 years
df2019_20 <- df
df2020_21 <- df
df2021_22 <- df

# budgets for 3 years
budget2019_20 <- 6000000
budget2020_21 <- 7000000
budget2021_22 <- 8000000

# into lists
df_list <- list(df2019_20, df2020_21, df2021_22)
budget_list <- list(budget2019_20, budget2020_21, budget2021_22)

I've written the following function to both apply the right year to Jan and fill in the rest by deparsing the respective dfs name. It works perfectly if I supply a single df and a single budget.

budget_func <- function(df, budget){ 
  
  df_name <- deparse(substitute(df))
  
  df <- df %>%
    mutate(year=ifelse(month=="Jan",
                       as.numeric(str_sub(df_name, -2))   2000,
                       as.numeric(str_extract(df_name, "\\d{4}(?=_)")))
    )
  
  for (i in 1:12){ 
    
    df[i,1] <- df[i,1] * budget
    
    i <- i 1
  }
  return(df)
}

To speed things up I want to pass both lists as arguments to mapply. However I don't get the results I want - what am I doing wrong?

final_budgets <- mapply(budget_func, df_list, budget_list)

CodePudding user response:

Instead of using deparse/substitute (which works when we are passing a single dataset, and is different in the loop because the object passed is not the object name), we may add a new argument to pass the names. In addition, when we create the list, it should have the names as well. We can either use list(df2019_20 = df2019_20, ...) or use setNames or an easier option is dplyr::lst which does return with the name of the object passed

budget_func <- function(df, budget, nm1){ 
           df_name <- nm1
  
             df <- df %>%
               mutate(year=ifelse(month=="Jan",
                                  as.numeric(str_sub(df_name, -2))   2000,
                                  as.numeric(str_extract(df_name, "\\d{4}(?=_)")))
               )
  
             for (i in 1:12){ 
    
               df[i,1] <- df[i,1] * budget
    
               i <- i 1
             }
             return(df)
           }

-testing

df_list <- dplyr::lst(df2019_20, df2020_21, df2021_22)
budget_list <- list(budget2019_20, budget2020_21, budget2021_22)
Map(budget_func, df_list, budget_list, names(df_list))     

-output

$df2019_20
   monthly_budget month year
1          360000   Feb 2019
2          780000   Mar 2019
3          420000   Apr 2019
4          360000   May 2019
5          600000   Jun 2019
6          360000   Jul 2019
7          360000   Aug 2019
8          540000   Sep 2019
9          360000   Oct 2019
10         360000   Nov 2019
11         600000   Dec 2019
12         900000   Jan 2020

$df2020_21
   monthly_budget month year
1          420000   Feb 2020
2          910000   Mar 2020
3          490000   Apr 2020
4          420000   May 2020
5          700000   Jun 2020
6          420000   Jul 2020
7          420000   Aug 2020
8          630000   Sep 2020
9          420000   Oct 2020
10         420000   Nov 2020
11         700000   Dec 2020
12        1050000   Jan 2021

$df2021_22
   monthly_budget month year
1          480000   Feb 2021
2         1040000   Mar 2021
3          560000   Apr 2021
4          480000   May 2021
5          800000   Jun 2021
6          480000   Jul 2021
7          480000   Aug 2021
8          720000   Sep 2021
9          480000   Oct 2021
10         480000   Nov 2021
11         800000   Dec 2021
12        1200000   Jan 2022
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