Start a new line after 4th element in list-CodePudding

I've written a code to print a Fibonacci sequence up to a certain value input by the user. I need the output to start a new line after every 4th element.

Here is my code:

number = int(input("Enter a positive number: \n"))
f1, f2 = 0, 1
count = 1
fibonacci = [f1]

while count < number:
        fn = f1   f2
        f1 = f2
        f2 = fn
        fibonacci.append(f1)
        count  = 1

print(fibonacci)

CodePudding user response：

While not changing priginal fibonacci list, you can print your values like this.

Instead of

print(fibonacci)

you could use this:

for i in range(0, len(fibonacci), 4):
     print(fibonacci[i:i 4])

CodePudding user response：

You already have a counter so I guess what you want is that every time it reaches a multiple of 4, use print('\n')

CodePudding user response：

number = int(input("Enter a positive number: "))
def fabronic(n):
   if n<=1:
      return n
   else:
      return fabronic(n-1) fabronic(n-2)
count,n=0,0
while n<number:
   print(fabronic(n),end=' ')
   count =1
   if count==4:
      print()
      count=0
   n=n 1  
input=Enter a positive number: 15    
output=   
0 1 1 2   
3 5 8 13   
21 34 55 89   
144 233 377     

By using list  

n=0
mylist=[]
while n<number:
    mylist.append(fabronic(n))
    n=n 1
for item in range(0,len(mylist),4):
    print(mylist[item:item 4],sep=' ',end='\n')  
output=  
Enter a positive number: 15  
[0, 1, 1, 2]  
[3, 5, 8, 13]  
[21, 34, 55, 89]  
[144, 233, 377]