I am trying to turn a python's keys into lists, however, some keys are empty and I get KeyError. To avoid the KeyError, I want it to return an empty string so I can easily append this to a dataframe. Also, I want an efficient/better way to run the code below, since I am retrieving a large amount of information, and implementing this process manually is very time consuming.

My code:

ages= []
names = []

for i in range(len(test)):
    
    try:   
        age= test[i]["age"]
        ages.append(age)

    except KeyError:
        age= ""
        ages.append(age)

    try:
        name = test[i]["name"]
        names.append(name)
        
    
    except KeyError:
        name = ""
        names.append(name)

I have many other data points from this dict that I want to retrieve such as weight, height, etc. and doing a try/except for all them can be tedious for code. Is there an efficient way to recreate this code.

CodePudding user response：

You can use the get method of dictionaries and also loop directly through your list:

ages= []
names = []
for t in test:
    ages.append(t.get("age", "")
    names.append(t.get("name", "")

CodePudding user response：

You can use the defaultdict collection instead of a simple dictionary.

It creates a default value for a "missing" key.

CodePudding user response：

1. test.items()

Will return list of key/value pairs. I.e. list of tuples.

2. test.keys()

Will return list of keys.

3. test.values()

Will return list of values.