Home > Software design >  firestore updateDoc replaces entire field instead of updating?
firestore updateDoc replaces entire field instead of updating?

Time:04-28

Im trying to figure what I am doing incorrectly here when I want to update just a value of my field in the firestore but instead the entire field got replaced?

also for whatever reason my date variable seems to directly become the string date in firestore instead of the value it holds?

Here's my code for updating the Doc:

export async function addLikesToFeed(date, likes){
    try{
        // it literally updates to {'date': 'likes: 1'}
        await updateDoc(doc(db, 'Bulletin', `bulletin`), { date: {likes: likes 1}})
    } catch(error){
        console.log('error updating Likes at addLikesToFeed: ', error.message)
    }
}

The below is a screen shot of my firestore. If I hard code '05-02-2022' in the date part, it becomes like what you see in the image. If I kept date as seen in the code, it becomes the date like part.

the date variable holds a string and likes is a number.

I want my function to work so that when I click on my button it will add one like to the value in the likes part, and I am trying to figure out why I cant do that

Thanks

enter image description here

CodePudding user response:

If you want to use the value of date as the field name, you can use [] notation:

await updateDoc(doc(db, 'Bulletin', `bulletin`), { [date]: {likes: likes 1}})

This will still replace the entire field for that date though. If you want to update only the likes subfield, you can use dot notation to update fields in nested objects:

await updateDoc(doc(db, 'Bulletin', `bulletin`), { [date ".likes"]: likes 1})

Finally, Firestore actually has a build in operator for incrementing values, which prevents race conditions when multiple users are updated the likes values at almost the same time.

  • Related