Define a function that splits a data sequence, prints each on new line but does not print specific i-CodePudding

I have a function I'm trying to define. I have it printing each data sequence onto a new line, however can I have it print/filter out specific indices?

Let's say my data sequence is:

ABC//DEF//64/G//HI/55/123/JKL

Can I adjust the function to also remove the indices for the numbered data so that it prints:

['ABC', '', 'DEF', '', '', '', 'G', '', '', 'HI', '', '', 'JKL']

Perhaps not only ignore the specific indices, but rather replace with a whitespace?

Thanks!

Code below:

  def split_lines(lines, delimiter):
  for line in lines:
    tokens = line.split(delimiter)
    print(tokens)

CodePudding user response：

To remove the digits you could use:

import re
def split_lines(lines, delimiter, to_remove='[0-9]'):
  for line in lines:
    tokens = line.split(delimiter)
    tokens = [re.sub(to_remove, '', token) for token in tokens]
    print(tokens)

or to remove the ones made only of digits:

import re
def split_lines(lines, delimiter, to_remove='^[0-9] $'):
  for line in lines:
    tokens = line.split(delimiter)
    tokens = [re.sub(to_remove, '', token) for token in tokens]
    print(tokens)

CodePudding user response：

Simple loops and some accumulation make it possible:

t = "ABC//DEF//64/G//HI/55/123/JK2L"

k = [[]] # start with empty inner list
for l in t:
    if l == "/":
        k.append([]) # add new inner list
    else:
        k[-1].append(l) # add to last inner list

# fix lists to strings or empty string
for i,v in enumerate(k):
    v = ''.join(v)  # combine inner list to string
    
    # store empty if string is all numbers, else store v
    k[i] = "" if v.isdigit() else v

print (k)
print ([o for o in k if o]) # remove empty values from list

to get

['ABC', '', 'DEF', '', '', 'G', '', 'HI', '', '', 'JK2L']
['ABC', 'DEF', 'G', 'HI', 'JK2L']