I have a file containing text like
0 de is 1568.1612302738604
1 de is 553.203055894161
2 de is 1593.492544682082
3 de is 1583.9043943157742
4 de is 1575.9076019892175
5 de is 1485.8005089881244
6 de is 988.1260339774907
I need to remove the first string from the text and remains numbers after de is
to be like that
1568.1612302738604
553.203055894161
1593.492544682082
1583.9043943157742
1575.9076019892175
1485.8005089881244
988.1260339774907
the code i tried is
import os
inputFile = open("file1", "r")
exportFile = open("file2", "w")
i = 0
for line in inputFile:
new_line= line.replace(str(i) " de is ",'')
exportFile.write(new_line)
i =1
exportFile.close()
but didn't work
CodePudding user response:
You could use regex for this
import re
key, your_decimal_number = re.findall('\d*\.?\d ',line)
index is 0 your decimal number is '1568.1612302738604'
if you do not need index you can use re.findall("\d \.\d ", line)
keep that in mind re.findall
returns a list
CodePudding user response:
lst = []
with open('test.txt') as f:
for line in f:
lst.append(line.split('de is ')[-1])
with open('test.txt','w') as f:
f.writelines(lst)