Regular expression to stop at specific character, return null if doesn't match-CodePudding

I have this string:

|AL;GF=0;ID=17;AF=122|CT;GF=0;ID=15;AF=123|BD;GF=0;ID=1;AF=124|

I want to match if CT block (have CT; between |) has ID=1, i tried:

/\|CT;.*?ID=1;(?=.*\|)/

But doesn't working.

Code:

let string = '|AL;GF=0;ID=17;AF=122|CT;GF=0;ID=15;AF=123|BD;GF=0;ID=1;AF=124|'
console.log(string.match(/\|CT;.*?ID=1;(?=.*\|)/g))

// return ['|CT;GF=0;ID=15;AF=123|BD;GF=0;ID=1;']
// expected null

Someone can help me?

CodePudding user response：

You can use

/\|CT;[^|]*ID=1;/

See the regex demo.

Details:

\|CT; - |CT; string
[^|]* - zero or more chars other than a | char
ID=1; - a fixed string.

See a JavaScript demo:

const strings = [
  '|AL;GF=0;ID=17;AF=122|CT;GF=0;ID=15;AF=123|BD;GF=0;ID=1;AF=124|',
  '|AL;GF=0;ID=17;AF=122|CT;GF=0;ID=1;AF=123|BD;GF=0;ID=1;AF=124|'
]
for (const string of strings) {
    console.log(string.match(/\|CT;[^|]*ID=1;/)?.[0]);
}