Random Lottery Number Generator without repeat sets?-CodePudding

Random gen() picks a repeated number, the same number as 33, 33, in a list. I want to get a different list from numbers [0.99]. What method should be used to fix the bug?

CodePudding user response：

the random library provide you with a function for this in sample

>>> import random
>>> random.sample(range(100),5)
[86, 27, 78, 74, 57]
>>>

if you only want one number you can use either choice or randint

>>> random.choice(range(100))
23
>>> random.randint(0,99)
77
>>>

CodePudding user response：

Here is a numpy solution using np.random.choice(). Setting the flag replace=False avoids duplicates.

import numpy as np

draws = 6
np.random.choice(range(0,100), draws, replace=False)

Instead of passing range(100), you could also pass 100, which will return numbers between 0-99.

Output:

array([76, 74,  2, 37, 96, 41])

CodePudding user response：

# import random (library to generate random numbers)
import random

# declare a variable l_number (lottery number) using the function random.choice()
l_number = random.choice(range(0, 100))

# print the lottery number
print(l_number)