I need to match files only with one specific extension under all nested directories, including the PWD, with BASH using "globbing".

• I do not need to Match all files under all nested directories with shell globbing, but not in the PWD.
• I do not need to only grep recursively, but only in files with certain extensions (plural)
• set -o globstar; ls **/*.* is great for all files (not my question).
  • ls **/*.php does not match in the PWD.
  • set -o globstar; **/*.php returns duplicate files.
• grep -r --include=\*.php "find me" ./ is specifically for grep, not globbing (consider this Question). It seems grep has --include=GLOB because this is not possible using globbing.

From this Answer (here), I believe there may not be a way to do this using globbing.

tl;dr

I need:

• A glob expression
• To match any command where simple globs can be used (ls, sed, cp, cat, chown, rm, et cetera)
• Mainly in BASH, but other shells would be interesting
• Both in the PWD and all subdirectories recursively
• For files with a specific extension

I'm using grep & ls only as examples, but I need a glob expression that applies to other commands also.

• grep -r --include=GLOB is not a glob expression for, say, cp; it is a workaround specific to grep and is not a solution.
• find is not a glob, but it may be a workaround for non-grep commands if there is no such glob expression. It would need | or while do;, et cetera.

Examples

Suppose I have these files, all containing "find me":

./file1.js
./file2.php
./inc/file3.js
./inc/file4.php
./inc.php/file5.js
./inc.php/file6.php

I need to match only/all .php one time:

./file2.php
./inc/file4.php
./inc.php/file6.php

Duplicates returned: shopt -s globstar; ... **/*.php

This changes the problem; it does not solve it.

Dup: ls

Before entering shopt -s globstar as a single command...

ls **/*.php returns:

inc/file4.php
inc.php/file5.js
inc.php/file6.php

• file2.php does not return.

After entering shopt -s globstar as a single command...

ls **/*.php returns:

file2.php
inc/file4.php
inc.php/file6.php

inc.php:
file5.js
file6.php

• inc.php/file6.php returns twice.

Dup: grep

Before entering shopt -s globstar as a single command...

grep -R "find me" **/*.php returns:

inc/file4.php: find me
inc.php/file6.php: find me

• file2.php does not return.

After entering shopt -s globstar as a single command...

grep -R "find me" **/*.php returns:

file2.php: find me
inc/file4.php: find me
inc.php/file5.js: find me
inc.php/file6.php: find me
inc.php/file6.php: find me

• inc.php/file6.php returns twice.
  • After seeing the duplicate seen from the ls output, we know why.

Current solution: faulty misuse of && logic

grep -r "find me" *.php && grep -r "find me" */*.php
ls -l *.php && ls -l */*.php

• Please no! I fail here && so I never happen

Desired solution: single command via globbing

grep -r "find me" [GLOB]
ls -l [GLOB]

---

Insight from grep

grep does have the --include flag, which achieves the same result but using a flag specific to grep. ls does not have an --include option. This leads me to believe that there is no such glob expression, which is why grep has this flag.

CodePudding user response：

With bash, you can first do a shopt -s globstar to enable recursive matching, and then the pattern **/*.php will expand to all the files in the current directory tree that have a .php extension.

zsh and ksh93 also support this syntax. Other commands that take a glob pattern as an argument and do their own expansion of it (like your grep --include) likely won't.

CodePudding user response：

With shell globing it's possible to only get directories by adding a / at the end of the glob, but there's no way to exclusively get files (zsh beeing an exception)

Illustration

With the given tree:

file.php
inc.php/include.php

**/*.php/ will expand to inc.php/, and **/*.php will expand to file.php inc.php inc.php/include.php

If you want to get file.php inc.php/include.php, then you cannot use a glob, that's all.
^{(with zsh, the glob for that would be **/*.php(.))}

Standard solution

The POSIX way to recursively get the files that match a given glob and then apply a command to them is to use find -type f -name ... -exec ...:

• ls -l <all .php files> would be:

find . -type f -name '*.php' -exec ls -l {}  

• grep "finde me" <all .php files> would be:

find . -type f -name '*.php' -exec grep "finde me" {}  

• cp <all .php files> ~/destination/ would be:

find . -type f -name '*.php' -type f -exec sh -c 'cp "$@" ~/destination/' _ {}  

CodePudding user response：

Suggesting different strategy:

Use explicit find command to build bash command(s) on the selected files using -printf option.

Inspect the command for correctness and run.

1. preparing bash commands on selected files

 find . -type f -name "*.php" -printf "cp %p ~/destination/ \n"

2. inspect the output, correct command, correct filter, test

cp ./file2.php ~/destination/
cp ./inc/file4.php ~/destination/
cp ./inc.php/file5.php ~/destination/

3. execute prepared find output

 bash <<< $(find . -type f -name "*.php" -printf "cp %f ~/destination/ \n")